What is 6 rooms 7 guys riddle?

The 6 rooms 7 guys riddle is a classic logic puzzle that involves a scenario where seven men need to be assigned to different rooms in a hotel. The puzzle usually goes as follows:

Seven guys have arrived at a hotel, but there are only six rooms available. The manager of the hotel decides to put two men in each room, but they end up with an extra guy. To solve the problem, the manager decides to put three men in one room, leaving two rooms with two men each. However, when they go to check-in, the three men in one room decide that it's too crowded and they ask for two of them to be moved to another room. So, one guy moves to a room with two guys, and two guys move to the room with the remaining single man.

The puzzle then asks, what is the minimum number of moves needed to get the three rooms back to having two people in each room?

The solution to this puzzle can be arrived at through logical deduction and trial and error. The minimum number of moves required to get the three rooms back to having two people in each room is two moves. The initial configuration of rooms and people can be represented as:

Room 1: 1, 2 Room 2: 3, 4 Room 3: 5, 6, 7

To get the men back to the desired configuration, the first move is to move guy 2 from room 1 to room 2, so the configuration becomes:

Room 1: 1 Room 2: 2, 3, 4 Room 3: 5, 6, 7

Next, we move guys 6 and 7 from room 3 to room 1, and the configuration becomes:

Room 1: 1, 6, 7 Room 2: 2, 3, 4 Room 3: 5

Finally, we move guy 7 from room 1 to room 2, and we get the desired configuration:

Room 1: 1, 6 Room 2: 2, 3, 4, 7 Room 3: 5

Thus, by making just two moves, we have managed to get the seven guys back to the desired configuration of 3 rooms with 2 men each.